C(x)=4000+0.3x^2+50x

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Solution for C(x)=4000+0.3x^2+50x equation: 



(C)=4000+0.3C^2+50C

We move all terms to the left:

(C)-(4000+0.3C^2+50C)=0

We get rid of parentheses

-0.3C^2-50C+C-4000=0

We add all the numbers together, and all the variables

-0.3C^2-49C-4000=0

a = -0.3; b = -49; c = -4000;
Δ = b2-4ac
Δ = -492-4·(-0.3)·(-4000)
Δ = -2399
Delta is less than zero, so there is no solution for the equation

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